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Question: Two parallel conducting plates of area ![](https://cdn.pureessence.tech/canvas_69.png?top_left_x=120...

Two parallel conducting plates of area each are placed 6 mm apart and are both earthed. A third plate, identical with the first two, is placed at a distance of 2 mm from one of the earthed plates and is given a charge of 1 C. The potential of the central plate is.

A

B

C

D

Answer

Explanation

Solution

: The plates 1 and 2 will form one capacitor and plates 2 and 3 will form another capacitor. These two capacitors are in parallel. Their effective capacitance is

Potential of central plate, V=QC=Q2 d3ε0 A\mathrm { V } = \frac { \mathrm { Q } } { \mathrm { C } } = \frac { \mathrm { Q } 2 \mathrm {~d} } { 3 \varepsilon _ { 0 } \mathrm {~A} }

=1×2×2×1033×8.85×1012×2.5=6×107 V= \frac { 1 \times 2 \times 2 \times 10 ^ { - 3 } } { 3 \times 8.85 \times 10 ^ { - 12 } \times 2.5 } = 6 \times 10 ^ { 7 } \mathrm {~V}