Question

Two nuclei have their mass numbers in the ratio of 1 : 3 the ratio of their nuclear densities would be

• A. $(3)^{1/3}:1$
• B. 1: 1
• C. 1 : 3
• D. 3 : 1

Answer 1

Answer: (B)

1: 1

Answer 2

: $A_{1}:A_{2} = 1:3$

Their radii will be in the ratio

$R_{0}A_{1}^{1/3}:R_{0}A_{2}^{1/3} = 1:3^{1/3}$

Density $\rho = \frac{A}{\frac{4}{3}\pi R^{3}}$

$\therefore\rho_{A_{1}}:\rho_{A_{2}} = \frac{1}{\frac{4}{3}\pi R_{0}^{3}.1^{3}}:\frac{3}{\frac{4}{3}\pi R_{0}^{3}.(3^{1/3})^{3}} = 1:1$

Their nuclear densities will be the same