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Question: Two non-reactive gases A and B present in a container with partial pressures \(200\) and \({{180mm}}...

Two non-reactive gases A and B present in a container with partial pressures 200200 and 180mm{{180mm}} of Hg{{Hg}}. When a third non-reactive gas C is added then total pressure becomes 1atm{{1atm}} then mole fraction of C will be:
A. 0.750.75
B. 0.50.5
C. 0.250.25
D. cannot be calculated

Explanation

Solution

The dissolved non-volatile solute lowers the vapor pressure. Dalton’s law and Raoult’s law can be used to solve this question. Raoult’s law states that the vapor pressure of a solution is directly proportional to the mole fraction of solvent. The solution which obeys Raoult’s law is called the ideal solution.

Complete step by step answer:
Here, three non-reactive gases are mixed together. Thus its total pressure will be the sum of the partial pressures of all these non-reactive gases. This is derived from Dalton’s law of partial pressures.
It is given that the partial pressure of gas A, pA=200mm{{{p}}_{{A}}} = 200{{mm}} of Hg{{Hg}}
Partial pressure of gas B, pB=180mm{{{p}}_{{B}}} = 180{{mm}} of Hg{{Hg}}
Partial pressure of gas C can be expressed as pC{{{p}}_{{C}}}.
Based on Dalton’s law of partial pressures, total pressure can be expressed as:
Total pressure, Pt=pA+pB+pC{{{P}}_{{t}}} = {{{p}}_{{A}}} + {{{p}}_{{B}}} + {{{p}}_{{C}}}
Substituting the values of partial pressures of A and B in the above equation, we get
Pt=200+180+pC{{{P}}_{{t}}} = {{200}} + {{180}} + {{{p}}_{{C}}}
Also, we know that the total pressure is given as 1atm{{1atm}} which is equal to 760mm760{{mm}} of Hg{{Hg}}.
Thus 760=200+180+pC{{760}} = {{200}} + {{180}} + {{{p}}_{{C}}}
Partial pressure of C, pC=760380=380mm{{{p}}_{{C}}} = 760 - 380 = 380{{mm}} of Hg{{Hg}}.
Now according to Raoult’s law,
Raoult’s law can be mathematically expressed as:
Partial pressure, p=xPt{{p}} = {{x}}{{{P}}_{{t}}}, where Pt{{{P}}_{{t}}}is the total vapor pressure and x{{x}}is the mole fraction.
Thus the partial pressure of C, pC=xPt{{{p}}_{{C}}} = {{x}}{{{P}}_{{t}}}
i.e. 380=x×760mm{{380}} = {{x}} \times {{760mm}} of Hg{{Hg}}
On simplification, we get
Mole fraction of C, x=380760=0.5{{x = }}\dfrac{{380}}{{760}} = 0.5
Thus the mole fraction of C is 0.50.5.

Hence, the correct option is B.

Note:
Vapor pressure of a liquid is much different in a solution than it is in pure liquid. Vapor pressure is the pressure acted over a substance at which vapors are formed. When a plot of vapor pressure of solution, Psoln{{{P}}_{{{soln}}}}, against mole fraction of solvent, Xsolvent{{{X}}_{{{solvent}}}}, is represented, it gives a straight line with a slope of Psolvent{{{P}}_{{{solvent}}}}.