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Question

Question: two mutually perpendicular long conducting wire carrying currents I1 and I2 lie in one plane. Locus ...

two mutually perpendicular long conducting wire carrying currents I1 and I2 lie in one plane. Locus of point at which magnetic induction is zero

Answer

I_1|x| = I_2|y|

Explanation

Solution

Assume wires are along x and y axes. Magnetic field from wire 1 (along x-axis) at P(x,y) is B1=μ0I12πyB_1 = \frac{\mu_0 I_1}{2\pi |y|}. Magnetic field from wire 2 (along y-axis) at P(x,y) is B2=μ0I22πxB_2 = \frac{\mu_0 I_2}{2\pi |x|}. For zero net magnetic field, B1B_1 and B2B_2 must be equal in magnitude and opposite in direction. Equating magnitudes gives μ0I12πy=μ0I22πx\frac{\mu_0 I_1}{2\pi |y|} = \frac{\mu_0 I_2}{2\pi |x|}, which simplifies to I1x=I2yI_1|x| = I_2|y|. The directions of fields cancel in two opposite quadrants, leading to two lines passing through the origin, y=±I1I2xy = \pm \frac{I_1}{I_2} x.