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Question: Two monochromatic light waves of amplitudes 3 A and 2 A interfering at a point have a phase differen...

Two monochromatic light waves of amplitudes 3 A and 2 A interfering at a point have a phase difference of 600. The intensity at that point will be proportional to :

A

5A2

B

13A2

C

7A2

D

19A2

Answer

19A2

Explanation

Solution

: Here, A1=3A,A2=2A,φ=60A_{1} = 3A,A_{2} = 2A,\varphi = 60{^\circ}

The resultant amplitude at a point is

R=A12+A22+2A1A2cosφR = \sqrt{A_{1}^{2} + A_{2}^{2} + 2A_{1}A_{2}\cos\varphi}

(3A)2+(2A)2+2×3A×2A×cos60\sqrt{(3A)^{2} + (2A)^{2} + 2 \times 3A \times 2A \times \cos 60{^\circ}}

=9A2+4A2+6A2=A19= \sqrt{9A^{2} + 4A^{2} + 6A^{2}} = A\sqrt{19}