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Question: Two moles of \(\mathrm { NH } _ { 3 }\) when put into a previously evacuated vessel (one litre), par...

Two moles of NH3\mathrm { NH } _ { 3 } when put into a previously evacuated vessel (one litre), partially dissociate into N2N _ { 2 }and H2H _ { 2 } . If at equilibrium one mole of NH3 is present, the equilibrium constant is.

A

3/4 mol 2^ { 2 } litre −2^ { - 2 }

B

27/64 mol 2^ { 2 } litre −2^ { - 2 }

C

27/32 mol 2^ { 2 } litre −2^ { - 2 }

D

27/1 mol 2^ { 2 } litre −2^ { - 2 }

Answer

27/1 mol 2^ { 2 } litre −2^ { - 2 }

Explanation

Solution

⇌; K[N2][H2]3[NH3]2=1×331=27K \frac { \left[ \mathrm { N } _ { 2 } \right] \left[ \mathrm { H } _ { 2 } \right] ^ { 3 } } { \left[ \mathrm { NH } _ { 3 } \right] ^ { 2 } } = \frac { 1 \times 3 ^ { 3 } } { 1 } = 27