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Question: Two moles of an ideal gas (C<sub>v</sub> = 12.5 J K<sup>–1</sup>mol<sup>–1</sup>) occupy a volume of...

Two moles of an ideal gas (Cv = 12.5 J K–1mol–1) occupy a volume of 2 dm3 at 300 K. If it is heated to 320 K to increase the volume to 4 dm3 the entropy change is –

A

11.5

B

8.3

C

13.1

D

9.3

Answer

13.1

Explanation

Solution

DS = n Cv In T2T1\frac{T_{2}}{T_{1}} + nR In V2V1\frac{V_{2}}{V_{1}}

= 2 × 12.5 × 2.303 log 320300\frac{320}{300} (2 × 8.314 × 2.303 log 42\frac{4}{2})

= 1.6 + 11.5 = 13.1 J K–1 mol–1