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Question: Two mole of argon are mixed with one mole of hydrogen, then C<sub>p</sub>/C<sub>v</sub> for the mixt...

Two mole of argon are mixed with one mole of hydrogen, then Cp/Cv for the mixture is nearly

A

1.2

B

1.3

C

1.4

D

1.5

Answer

1.4

Explanation

Solution

Average degree of freedom

fav = 2×3+1×52+3=115\frac{2 \times 3 + 1 \times 5}{2 + 3} = \frac{11}{5}

νmix = 1 + 1fav\frac{1}{f_{av}} = 1 + 511\frac{5}{11} = 1611\frac{16}{11} = 1.4

Hence, C is correct Answer.