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Question

Question: Find the location of image after reflection from concave mirror....

Find the location of image after reflection from concave mirror.

A

30 cm to left of P1

B

30 cm to left of P2

C

30 cm right to P1

D

30 cm right to P2

Answer

30 cm to left of P1

Explanation

Solution

1. Identify the given parameters for the concave mirror:

  • The object is placed in front of the concave mirror.
  • Radius of curvature of the concave mirror, R=20R = 20 cm.
  • Focal length of the concave mirror, f=R2=202=10f = \frac{R}{2} = \frac{20}{2} = 10 cm. Since it is a concave mirror, according to the sign convention (light travels from left to right, and the mirror pole P1 is the origin), the focal length is negative: f=10f = -10 cm.
  • Object distance from the concave mirror, u=15u = 15 cm. Since the object is placed to the left of the concave mirror (P1), according to the sign convention, the object distance is negative: u=15u = -15 cm.

2. Apply the mirror formula:

The mirror formula is given by: 1f=1v+1u\frac{1}{f} = \frac{1}{v} + \frac{1}{u}

Substitute the values of ff and uu: 110=1v+115\frac{1}{-10} = \frac{1}{v} + \frac{1}{-15}

Rearrange the equation to solve for vv: 1v=110115\frac{1}{v} = \frac{1}{-10} - \frac{1}{-15} 1v=110+115\frac{1}{v} = -\frac{1}{10} + \frac{1}{15}

Find a common denominator, which is 30: 1v=330+230\frac{1}{v} = -\frac{3}{30} + \frac{2}{30} 1v=3+230\frac{1}{v} = \frac{-3 + 2}{30} 1v=130\frac{1}{v} = \frac{-1}{30}

Therefore, v=30v = -30 cm.

3. Interpret the result:

The negative sign for vv indicates that the image is formed on the same side as the object (in front of the mirror, which is to the left of P1). The magnitude of vv is 30 cm. So, the image is formed 30 cm to the left of the concave mirror (P1).