Question

Two metals $X$ and $Y$ belong to the second group of periodic table. $X$ forms insoluble oxide but soluble sulphate. $Y$ forms a soluble oxide but insoluble sulphate. Hydroxide of metal $X$ is soluble in $NaOH$ while that of metal $Y$ is insoluble in $NaOH$. What are metals $X$ and $Y$ ?

• A. $X = Be$, $Y = Ba$
• B. $X = Mg$, $Y=Ca$
• C. $X= Ca$, $Y = Sr$
• D. $X = Ba$, $Y = Mg$

Answer 1

Answer: (A)

$X = Be$, $Y = Ba$

Answer 2

$BeO$ - Insoluble, $BeSO_4$ - Soluble $BaO$ - Soluble, $BaSO_4$ - Insoluble $Be(OH)_2$ - Soluble in $NaOH$ $Ba(OH)_2$ - Insoluble in $NaOH$