Question

Two metallic wires $P$ and $Q$ have the same volume and are made of the same material. If their areas of cross-section are in the ratio $4 : 1$ and a force $F_1$ is applied to $P$, producing an extension of $\Delta l$, the force required to produce the same extension in $Q$ is $F_2$.The value of $\frac{F_1}{F_2}$ is _______.

Answer 1

The Correct Answer is