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Question: Two metallic spheres S<sub>1</sub> and S<sub>2</sub> are made of the same material and have identica...

Two metallic spheres S1 and S2 are made of the same material and have identical surface finish. The mass of S1 is three times that of S2. Both the spheres are heated to the same high temperature and placed in the same room having lower temperature but are thermally insulated from each other. The ratio of the initial rate of cooling of S1 to that of S2 is

A

1/ 3

B

(1/ 3)1/ 3

C

1/31/\sqrt{3}

D

3/1\sqrt{3}/1

Answer

(1/ 3)1/ 3

Explanation

Solution

dTdt=eAσmc(T4T04)\frac{dT}{dt} = \frac{eA\sigma}{mc}(T^{4} - T_{0}^{4})

∴ Rate of cooling R4πr243πr3×ρ1rR \propto \frac{4\pi r^{2}}{\frac{4}{3}\pi r^{3} \times \rho} \propto \frac{1}{r}R1R2=r2r1\frac{R_{1}}{R_{2}} = \frac{r_{2}}{r_{1}}

But according to problem m1 = 3m2

43πr13×ρ=3(43πr23×ρ)\frac{4}{3}\pi r_{1}^{3} \times \rho = 3\left( \frac{4}{3}\pi r_{2}^{3} \times \rho \right)r13=3r23r_{1}^{3} = 3r_{2}^{3}(r2r1)=(13)1/3\left( \frac{r_{2}}{r_{1}} \right) = \left( \frac{1}{3} \right)^{1/3}∴ Ratio of rate of cooling R1R2=(13)1/3\frac{R_{1}}{R_{2}} = \left( \frac{1}{3} \right)^{1/3}.