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Question: Two metal wires of identical dimensions are connected in series. If \(\sigma _ { 1 }\)and \(\sigma ...

Two metal wires of identical dimensions are connected in series. If σ1\sigma _ { 1 }and σ2\sigma _ { 2 } and are the conductivities of the metals respectively, the effective conductivity of the combination is

A

σ1+σ2\sigma _ { 1 } + \sigma _ { 2 }

B

σ1+σ22\frac { \sigma _ { 1 } + \sigma _ { 2 } } { 2 }

C

σ1σ2\sqrt { \sigma _ { 1 } \sigma _ { 2 } }

D

2σ1σ2σ1+σ2\frac { 2 \sigma _ { 1 } \sigma _ { 2 } } { \sigma _ { 1 } + \sigma _ { 2 } }

Answer

2σ1σ2σ1+σ2\frac { 2 \sigma _ { 1 } \sigma _ { 2 } } { \sigma _ { 1 } + \sigma _ { 2 } }

Explanation

Solution

: Resistance of a wire in terms of conductivity is given by

where l is the length and A is the area of cross – section of wire respectively.

As the wires are onnected in series,

Rs=R1+R2\therefore \mathrm { R } _ { \mathrm { s } } = \mathrm { R } _ { 1 } + \mathrm { R } _ { 2 }

where is the effective conductivity