Question

Two men are on the opposite side of a tower. They measure the angles of elevation of the top of the tower $30 ^ { \circ }$ respectively. If the height of the tower is 40m, find the distance between the men

• A. 40 m
• B. $40 \sqrt { 3 } m$
• C. 68.280 m
• D. 109.28 m

Answer 1

Answer: (D)

109.28 m

Answer 2

$O A = \frac { 40 } { \tan 45 ^ { \circ } }$

$= 40 [ 1 + \sqrt { 3 } ]$

$= 40 [ \sqrt { 3 } + 1 ]$ $= 40 \times 2.732 = 109.28$ metre