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Question: Two masses \(m _ { 1 }\) and \(m _ { 2 }\) are attached to a string which passes over a friction...

Two masses m1m _ { 1 } and m2m _ { 2 } are attached to a string which passes over a frictionless smooth pulley. When m1=10 kgm _ { 1 } = 10 \mathrm {~kg} m2=6 kgm _ { 2 } = 6 \mathrm {~kg} the acceleration of masses is

A

20 m/s2m / s ^ { 2 }

B

5m/s25 m / s ^ { 2 }

C

2.5 m/s2m / s ^ { 2 }

D

10 m/s210 \mathrm {~m} / \mathrm { s } ^ { 2 }

Answer

2.5 m/s2m / s ^ { 2 }

Explanation

Solution

a=m1m2m1+m2ga = \frac { m _ { 1 } - m _ { 2 } } { m _ { 1 } + m _ { 2 } } g =(10610+6)10= \left( \frac { 10 - 6 } { 10 + 6 } \right) 10 =2.5 m/s2= 2.5 \mathrm {~m} / \mathrm { s } ^ { 2 }