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Question

Physics Question on System of Particles & Rotational Motion

Two masses m1m_1 and m2m_2 are connected by a massless string over a fixed pulley. If m1>m2m_1 > m_2 , m1m_1 will move downward and m2m_2 will move upward. What is the acceleration with which the combination o f two masses will move? ( g=g = acceleration due to gravity)

A

00

B

gg

C

[(m1m2)/(m1+m2)]×g[(m_1 - m_2)/(m_1 + m_2)] \times g

D

[2m1m2/(m1+m2)]×g[2m_1m_2 /(m_1 + m_2)] \times g

Answer

[(m1m2)/(m1+m2)]×g[(m_1 - m_2)/(m_1 + m_2)] \times g

Explanation

Solution

a=(m1m2)×g(m1+m2)a=\frac{\left(m_{1}-m_{2}\right)\times g}{\left(m_{1}+m_{2}\right)}