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Question

Physics Question on Newtons Laws of Motion

Two masses m1=5kgm_{1}=5\,kg and m2=4.8kgm_{2}=4.8\,kg tied to a string are hanging over a light frictionless pulley. What is the acceleration of the masses when lift is free to move ? (g=9.8m/s2)(g=9.8 \, m/s^{2})

A

0.2m/s20.2\,m/s^{2}

B

9.8m/s29.8\,m/s^{2}

C

5m/s25\,m/s^{2}

D

4.8m/s24.8\,m/s^{2}

Answer

0.2m/s20.2\,m/s^{2}

Explanation

Solution

On releasing, the motion of the system will be according to figure. m1gT=m1am_{1} g-T=m_{1} a \ldots (i) and Tm2g=m2aT-m_{2} g=m_{2} a \ldots (ii) On solving; a=(m1m2m1+m2)g....a=\left(\frac{m_{1}-m_{2}}{m_{1}+m_{2}}\right) g ....(iii) Here, m1=5kg,m2=4.8kg,g=9.8m/s2m_{1}=5 \,kg , m_{2}=4.8 \,kg , g=9.8\, m / s ^{2} a=(54.85+4.8)×9.8 \therefore a=\left(\frac{5-4.8}{5+4.8}\right) \times 9.8 =0.29.8×9.8=0.2m/s2=\frac{0.2}{9.8} \times 9.8=0.2\, m / s ^{2}