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Question: Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictio...

Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown. The coefficient of static friction of A with table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is

A

15 kg

B

10 kg

C

5 kg

D

12 kg

Answer

15 kg

Explanation

Solution

For limiting condition

μ=mBmA+mC\mu = \frac { m _ { B } } { m _ { A } + m _ { C } }0.2=510+mC0.2 = \frac { 5 } { 10 + m _ { C } }

2+0.2mC=52 + 0.2 m _ { C } = 5mC=15 kgm _ { C } = 15 \mathrm {~kg}