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Question: Two loops P and Q are made from a uniform wire. The radii of P and Q are r<sub>1</sub> and r<sub>2</...

Two loops P and Q are made from a uniform wire. The radii of P and Q are r1 and r2 respectively, and their moments of inertia are I1 and I2 respectively. If I2 = 4I1 , then equals –

A

42/3

B

41/3

C

4–2/3

D

4–1/3

Answer

41/3

Explanation

Solution

I = MR2 = (2pRAd)R2

or I µ R3

or R µ I1/3

or = = (41)1/3\left( \frac { 4 } { 1 } \right) ^ { 1 / 3 }