Question

Two long parallel wires carrying currents $8 A$ and $15 A$ in opposite directions are placed at a distance of $7 cm$ from each other A point $P$ is at equidistant from both the wires such that the lines joining the point $P$ to the wires are perpendicular to each other The magnitude of magnetic field at $P$ is___$\times 10^{-6} T$(Given : $\sqrt{2}=1.4$ )

Answer 1

The correct answer is 68

Magnetic fields due to both wires will be perpendicular to each other.
B1​=2πdμ0​i1​​B2​=2πdμ0​i2​​
Bnet​=B12​+B22​​⇒2πdμ0​​i12​+i22​​
⇒2π×(7/2​)×10−24π×10−7​×82+152​(d=2​7​cm)
⇒68×10−6T