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Question: Two long parallel wires are hung by 4 cm long cords from a common axis. The wires have mass 0.0125 k...

Two long parallel wires are hung by 4 cm long cords from a common axis. The wires have mass 0.0125 kg/m and carry equal currents in opposite direction. Find the current in each wire if the cords hang at 60 with the vertical as shown in Fig. (1) –

A

11.2 A

B

22.3 A

C

717 A

D

71.7 A

Answer

22.3 A

Explanation

Solution

dFdl\frac { \mathrm { dF } } { \mathrm { dl } }rep == T sin 6bmg4\frac { \mathrm { mg } } { 4 }= T cos 60

tan 60 =μ0I24πdmg\frac { \mu _ { 0 } \mathrm { I } ^ { 2 } } { 4 \pi \mathrm { dmg } }=tan6(4π4sin6)mg×102μ0\sqrt { \frac { \tan 6 ^ { \circ } \left( 4 \pi 4 \sin 6 ^ { \circ } \right) \mathrm { mg } \times 10 ^ { - 2 } } { \mu _ { 0 } } }

=(.1)2×4π×4×.0.125×10×1024π×107\sqrt { \frac { ( .1 ) ^ { 2 } \times 4 \pi \times 4 \times .0 .125 \times 10 \times 10 ^ { - 2 } } { 4 \pi \times 10 ^ { - 7 } } }= 22.3 A

Fig. (2) Fig. (3)

tan 60 = sin 60 =6×π180\frac { 6 \times \pi } { 180 }= .1