Question

Two long current carrying thin wires, both with current $I$, are held by insulating threads of length $L$ and are in equilibrium as shown in the figure, with threads making an angle $'\theta'$ with the vertical. If wires have mass $\lambda$ per unit length then, the value of $I$ is : ( $g =$ gravitational acceleration)

• A. $2\sin\theta\sqrt{\frac{\pi \lambda gL}{\mu_0 \cos\theta}}$
• B. $\sin\theta\sqrt{\frac{\pi \lambda gL}{\mu_0 \cos\theta}}$
• C. $2\sqrt{\frac{\pi gL}{\mu_0}\tan \theta}$
• D. $\sqrt{\frac{\pi \lambda gL}{\mu_0}\tan \theta}$

Answer 1

Answer: (A)

$2\sin\theta\sqrt{\frac{\pi \lambda gL}{\mu_0 \cos\theta}}$

Answer 2