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Question: Two long and parallel wires are at a distance of 0.1 m and a current of 5 A is flowing in each of th...

Two long and parallel wires are at a distance of 0.1 m and a current of 5 A is flowing in each of these wires. The force per unit length due to these wires will be

A

5×10−5 N/m5 \times 10 ^ { - 5 } \mathrm {~N} / \mathrm { m }

B

5×10−3 N/m5 \times 10 ^ { - 3 } \mathrm {~N} / \mathrm { m }

C

2.5×10−5 N/m2.5 \times 10 ^ { - 5 } \mathrm {~N} / \mathrm { m }

D

2.5×10−4 N/m2.5 \times 10 ^ { - 4 } \mathrm {~N} / \mathrm { m }

Answer

5×10−5 N/m5 \times 10 ^ { - 5 } \mathrm {~N} / \mathrm { m }

Explanation

Solution

F=μ04π2×i1i2a=10−7×2×5×50.1=5×10−5 N/mF = \frac { \mu _ { 0 } } { 4 \pi } \frac { 2 \times i _ { 1 } i _ { 2 } } { a } = \frac { 10 ^ { - 7 } \times 2 \times 5 \times 5 } { 0.1 } = 5 \times 10 ^ { - 5 } \mathrm {~N} / \mathrm { m }