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Question: Two liquids are at temperature 20<sup>0</sup>C and 40<sup>0</sup>C. When same mass of both of them i...

Two liquids are at temperature 200C and 400C. When same mass of both of them is mixed, the temperature of the mixture is 320C. What is the ratio of the their specific heats ?

A

1/3

B

2/3

C

1/5

D

2/5

Answer

2/3

Explanation

Solution

msA(32 – 20) = msB (40 – 32) 12sA = 8sB

sAsB\frac{s_{A}}{s_{B}} = 23\frac{2}{3}