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Question: Two liquids A and B have P<sub>A</sub><sup>0</sup> : P<sub>B</sub><sup>0</sup> = 1 : 3 at a certain ...

Two liquids A and B have PA0 : PB0 = 1 : 3 at a certain temperature. If the mole fraction ratio of xA : xB = 1 : 3, the mole fraction of A in vapour in equilibrium with the solution at a given temperature is -

A

0.1

B

0.2

C

0.5

D

1.0

Answer

0.1

Explanation

Solution

yA = PA0XAPA0XA+PB0XB\frac{P_{A}^{0}X_{A}}{P_{A}^{0}X_{A} + P_{B}^{0}X_{B}}

yA = 11+PB0XBPA0XA\frac{1}{1 + \frac{P_{B}^{0}X_{B}}{P_{A}^{0}X_{A}}}

yA = 11+(3)(3)\frac{1}{1 + (3)(3)}= 110\frac{1}{10} = 0.1