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Question: Two lines are given by (x – 2y)<sup>2</sup> + k (x – 2y) = 0. The value of k, so that the distance b...

Two lines are given by (x – 2y)2 + k (x – 2y) = 0. The value of k, so that the distance between them is 3 is

A

k = 0

B

k = ± 3√5

C

k = -5

D

k = 3

Answer

k = ± 3√5

Explanation

Solution

The lines x – 2y = 0 and x – 2y + k = 0 are parallel. The distance between these two lines =

⇒ k = ± 3√5.