Solveeit Logo

Question

Physics Question on Nuclei

Two lighter nuclei combine to from a comparatively heavier nucleus by the relation given below: 12X+12X=24Y^2_1X+^2_1X=^4_2Y. The binding energies per nucleon for, 12X^2_1X and 24Y^4_2Y are 1.1 MeV and 7.6 MeV respectively. The energy released in the process is ______ MeV.

Answer

Energy released =Change in B.E.\text{Energy released }= \text{Change in B.E.}

(7.6×4)[4×1.1]=26  MeV(7.6 × 4) – [4 × 1.1] = 26 \;MeV