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Question

Physics Question on Refraction of Light

Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be:

A

2 : 3

B

16 : 81

C

25 : 169

D

25 : 1

Answer

25 : 1

Explanation

Solution

ImaxImin=(I1+I2I2I2)2=(51)2\frac{I_{max}}{I_{min}} = \bigg(\frac{\sqrt{I_1}+\sqrt{I_2}}{\sqrt{I_2}-\sqrt{I_2}}\bigg)^2 = \bigg(\frac{5}{1}\bigg)^2

= 251\frac{25}{1}