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Question: Two large thin metal plates are parallel and close to each other. On their inner faces, the plates h...

Two large thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and magnitude27×10−22Cm−227 \times 10^{- 22}Cm^{- 2}. The electric field E→\overrightarrow{E}in region it in between the plates is.

A

4.25×10−8NC−14.25 \times 10^{- 8}NC^{- 1}

B

6.28×10−10NC−16.28 \times 10^{- 10}NC^{- 1}

C

3.05×10−10NC−13.05 \times 10^{- 10}NC^{- 1}

D

5.03×10−10NC−15.03 \times 10^{- 10}NC^{- 1}

Answer

3.05×10−10NC−13.05 \times 10^{- 10}NC^{- 1}

Explanation

Solution

: The value of E→\overrightarrow{E}in the region II, in between the plates,

=σε0=27×10−228.88×10−12=3.05×10−10NC−1= \frac{\sigma}{\varepsilon_{0}} = \frac{27 \times 10^{- 22}}{8.88 \times 10^{- 12}} = 3.05 \times 10^{- 10}NC^{- 1}