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Physics Question on Gauss Law

Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude 16×10−22 C m−216 \times 10^{-22}\, C\, m^{-2}. The electric field between the plates is

A

1.8×10−10 N C−11.8 \times 10^{-10}\, N\, C^{-1}

B

1.9×10−10 N C−11.9 \times 10^{-10}\, N\, C^{-1}

C

1.6×10−10 N C−11.6 \times 10^{-10}\, N\, C^{-1}

D

1.5×10−10 N C−11.5 \times 10^{-10}\, N\, C^{-1}

Answer

1.8×10−10 N C−11.8 \times 10^{-10}\, N\, C^{-1}

Explanation

Solution

Here, E=σε0E=\frac{\sigma}{\varepsilon_{0}} =16×10−228.854×10−12=\frac{16\times10^{-22}}{8.854\times10^{-12}} =1.8×10−10 N C−1=1.8\times10^{-10}\,N\,C^{-1}