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Question: Two lamps of luminous intensity of 8 Cd and 32 Cd respectively are lying at a distance of 1.2 m from...

Two lamps of luminous intensity of 8 Cd and 32 Cd respectively are lying at a distance of 1.2 m from each other. Where should a screen be placed between two lamps such that its two faces are equally illuminated due to two sources

A

10 cm from 80 Cd lamp

B

10 cm from 32Cd lamp

C

40 cm from 8 Cd lamp

D

40 cm from 32 Cd lamp

Answer

40 cm from 8 Cd lamp

Explanation

Solution

I=Lr2L1L2=r12r22I = \frac{L}{r^{2}} \Rightarrow \frac{L_{1}}{L_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} or 8x2=32(120x)2\frac{8}{x^{2}} = \frac{32}{(120 - x)^{2}}

Solving it we get x=40cmx = 40cm.