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Question: Two lamps of 2000 and 1000 candle power respectively are suspended 30 ft above the ground and are 10...

Two lamps of 2000 and 1000 candle power respectively are suspended 30 ft above the ground and are 100 ft apart. Find the intensity of illumination at a point on the ground in line with the lamps between them and 40 ft from the base of the more powerful lamp –

A

0.48 ft-candle

B

0.58 m-candle

C

0.58 ft-candle

D

0.38 ft-candle

Answer

0.58 ft-candle

Explanation

Solution

I =L1cosθ1r12\frac{L_{1}\cos\theta_{1}}{r_{1}^{2}}+L2cosθ2r22\frac{L_{2}\cos\theta_{2}}{r_{2}^{2}}=L1hr13\frac{L_{1}h}{r_{1}^{3}}+L2hr23\frac{L_{2}h}{r_{2}^{3}}

I =2000×30503\frac{2000 \times 30}{50^{3}}+1000×30(67.08)3\frac{1000 \times 30}{(67.08)^{3}}= 0.48 + 0.1 = 0.58 ft-candle

Therefore the answer is (3).