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Question: Two insulated charged metallic spheres P and Q have their centres separated by a distance of 60 cm. ...

Two insulated charged metallic spheres P and Q have their centres separated by a distance of 60 cm. The radii of P and Q are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is

3.2×10−7C3.2 \times 10^{- 7}C is.

A

5.2×10−4N5.2 \times 10^{- 4}N

B

2.5×10−3N2.5 \times 10^{- 3}N

C

1.5×10−3N1.5 \times 10^{- 3}N

D

3.5×10−4N3.5 \times 10^{- 4}N

Answer

2.5×10−3N2.5 \times 10^{- 3}N

Explanation

Solution

: Here, q1=q2=3.2×10−7C,r=60cm=0.6mq_{1} = q_{2} = 3.2 \times 10^{- 7}C,r = 60cm = 0.6m

Electrostatic force, F=14πε0q1q2r2F = \frac{1}{4\pi\varepsilon_{0}}\frac{q_{1}q_{2}}{r^{2}}

=9×109(3.2×10−7)2(0.6)2=2.56×10−3N= \frac{9 \times 10^{9}(3.2 \times 10^{- 7})^{2}}{(0.6)^{2}} = 2.56 \times 10^{- 3}N