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Question: Two infinite sheets carry equal and opposite uniform charge of densities \(\pm \sigma\). The electri...

Two infinite sheets carry equal and opposite uniform charge of densities ±σ\pm \sigma. The electric field in the free space between the two sheets will be:
a). σϵ0\dfrac{\sigma}{{\epsilon}_{0}}
b). σ2ϵ0\dfrac{\sigma}{2{\epsilon}_{0}}
c). 2σϵ0\dfrac{2\sigma}{{\epsilon}_{0}}
d). Zero

Explanation

Solution

Hint: Since the two electric plates are oppositely charged and are infinite, we can neglect the fringing effect here and by using the Gauss law, we can calculate the electric field in the free space between the two sheets.

Complete step by step solution:

It has been given that two infinite sheets carry opposite uniform charges of densities +σ+\sigma and σ-\sigma respectively, which we can represent as below

Taking the direction towards right as positive, and by using Gauss law the electric field by a infinitely long charged sheet can be given by E=σ2ϵ0E=\dfrac{\sigma}{2{\epsilon}_{0}}, where σ\sigma is the charge density and ϵ0{\epsilon}_{0} is the permittivity.
So, the electric field from the sheet with the positive charge density, E=σ2ϵ0E’=\dfrac{\sigma}{2{\epsilon}_{0}} ………. (i)
And electric field due to the sheet with negative charge density,
E’’=σ2ϵ0E’’=-\dfrac{\sigma}{2{\epsilon}_{0}} ………. (ii)
Now, we need to find the electric field in the space between the two charged sheets,
Therefore, E=EE’’=(σ2ϵ0)(σ2ϵ0)=σϵ0E=E’-E’’=(\dfrac{\sigma}{2{\epsilon}_{0}})-(-\dfrac{\sigma}{2{\epsilon}_{0}})=\dfrac{\sigma}{{\epsilon}_{0}}
Hence, option a is the correct answer.
Additional information:
Gauss law states that electric flux through any hypothetical closed surface is always equal to the 1ϵ0\dfrac{1}{{\epsilon}_{0}} times of the net electric charge within that closed surface. It is given by the relation
ΦE=Qϵ0{\Phi}_{E}=\dfrac{Q}{{\epsilon}_{0}}, where Q is the charge in the closed surface and ϵ0{\epsilon}_{0} is the permittivity of the medium in which the closed surface is present.

Note: It should be noted that for a positively charged sheet the electric field lines will be in a direction away from the sheet while that of for a negatively charged sheet, its direction will be towards the sheet itself. So, direction should be considered carefully or else we can get ambiguous answers.