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Question

Physics Question on Inductance

Two inductors L1 L_1 and L2L_2 are connected in parallel and a time varying current flows as shown in figure. Then the ratio of currents i1/i2 i_1/i_2 at any time t is

A

L1/L2 L_1/ L_2

B

L2/L1 L_2/ L_1

C

L12(L1+L2)2 \frac{ L_1^2 }{ (L_1 + L_2)^2 }

D

L22(L1+L2)2 \frac{ L_2^2 }{ (L_1 + L_2)^2 }

Answer

L2/L1 L_2/ L_1

Explanation

Solution

Since L1L _{1} and L2L _{2} are connected in parallel. Potential difference across L1L _{1} is equal to that across L2L _{2} i.e. E1=E2E _{1}= E _{2} Or L1di1dt=L2dI2dt- L _{1} \frac{ di _{1}}{ dt }=- L _{2} \frac{ dI _{2}}{ dt } Or L1di1=L2di2L _{1} \int di _{1}= L _{2} \int di _{2} Or L2i2=L1i1L _{2} i _{2}= L _{1} i _{1} Or i1i2=L2L1\frac{ i _{1}}{ i _{2}}=\frac{ L _{2}}{ L _{1}}