Question

Two inductors each of $50mH$ are connected in parallel, what is the equivalent inductance?

Answer 1

When inductors are connected in parallel, the equivalent inductance $(L_eq)$ can be calculated using the formula:
$1/L_eq = 1/L1 + 1/L2 + 1/L3 + .….$
In this case, you have two inductors each with an inductance of $50 mH.$ Plugging in the values into the formula:
$1/L_eq = 1/50mH + 1/50mH$
To add the fractions, you need a common denominator:
$1/L_eq = (1/50mH + 1/50mH)/(1mH)$
Simplifying the numerator:
$1/L_eq = (2/50mH)/(1mH)$
$1/L_eq = 2/50$
Inverting both sides:
$L_eq = 50/2$
$L_eq = 25 mH$
Therefore, the equivalent inductance of two $50 mH$ inductors connected in parallel is $25 mH.$