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Question

Question: Two identical spring of constant K are connected in series and parallel as shown in figure. A mass m...

Two identical spring of constant K are connected in series and parallel as shown in figure. A mass m is suspended from them. The ratio of their frequencies of vertical oscillations will be

A

2 : 1

B

1 : 1

C

1 : 2

D

4 : 1

Answer

1 : 2

Explanation

Solution

n=12πkmn = \frac { 1 } { 2 \pi } \sqrt { \frac { k } { m } }nSnP=kSkP\frac { n _ { S } } { n _ { P } } = \sqrt { \frac { k _ { S } } { k _ { P } } } \Rightarrow nsnp=(k2)2k=12\frac { n _ { s } } { n _ { p } } = \sqrt { \frac { \left( \frac { k } { 2 } \right) } { 2 k } } = \frac { 1 } { 2 }