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Question: Two identical spheres \(A\) and \(B\) having an equal charge repel with each other with force \(100\...

Two identical spheres AA and BB having an equal charge repel with each other with force 100N100\,N. When they are placed 10cm10\,cm apart in a medium of dielectric constant 5. Now, determine charge on each sphere:

Explanation

Solution

Coulomb's law states, the magnitude electrostatic force of attraction or repulsion. Two electrical charged bodies is directly proportional to product of the charged bodies and inversely proportional to the square of the distance between the Centre charged bodies.

Complete step by step answer:
Given that two spheres AA and BB having equal charges,
Here FF is force with 100N100\,N
Medium dielectric constant is k1=5{k_1} = 5
Distance between these two spheres is 10cm10\,cm.

From coulomb's law, we know that
F=kq2k1r2F = \dfrac{{k{q^2}}}{{{k_1}{r^2}}}
Here qq represents quantity of charges,
Where as, we known from coulomb’s law constant,
k=14πeok = \dfrac{1}{{4\pi {e_o}}}
Now substitute all the values in FF, then we get
100=14πeo×q25(10×102)2100 = \dfrac{1}{{4\pi {e_o}}} \times \dfrac{{{q^2}}}{{5{{(10 \times {{10}^{ - 2}})}^2}}}
From coulombs theorem we know,
k=14πeo=9×109k = \dfrac{1}{{4\pi eo}} = 9 \times {10^9}
Now we get,
100 = \dfrac{{9 \times {{10}^9} \times {q^2}}}{{5 \times {{\left( {10 \times {{10}^{ - 2}}} \right)}^2}}} \\\ \Rightarrow {q^2} = \dfrac{{100 \times 5 \times {{10}^{ - 2}}}}{{9 \times {{10}^9}}} \\\ \Rightarrow {q^2} = \dfrac{{100 \times 5}}{9} \times {10^{ - 11}} \\\ \Rightarrow {q^2} = \dfrac{{500}}{9} \times {10^{ - 11}} \\\
q=23.910C\therefore q = 23.9 \sim 10\,C

Additional information: Coulombs discovered by the 1785 by French physicist Charles Augustin de Coulomb. This law is essential for the theory of electromagnetism. Coulombs value is approximately k=9×109k = 9 \times {10^9}. Coulomb's law is stated as the simple mathematical expression. From Coulomb's law we can define the Scalar form of the law and Vector form of the law. Coulomb's law holds even with the atoms. Gauss’s law can be derived from Coulomb's law and Coulombs can be derived from Gauss’s law .

Note: Gauss’s law can be derived from Coulomb's law and Coulombs can be derived from Gauss’s law. If any two spheres repel each other with the same force and apart some distance in medium of dielectric constant then we can calculate and solve it by using Coulomb's law. In order to find out the extent of repulsion or attraction.