Solveeit Logo

Question

Physics Question on Gravitation

Two identical satellites AA and BB revolve around the earth in circular orbits at distance RR and 3R3R from the surface of the earth. The ratio of the linear momenta of AA and BB is (RR = radius of the earth)

A

1:11 : 1

B

1:21 : \sqrt{2}

C

2:1 \sqrt{2} : 1

D

2:12 : 1

Answer

2:1 \sqrt{2} : 1

Explanation

Solution

Linear momentum of satellite, p=mυ0=mGM/ri.e,p1/r;p = m \upsilon_0 = m \sqrt{GM/ r} \:\:\: i.e, \, p \propto 1 /\sqrt{r} ; pApB=rBrA=R+3RR+R=2 \therefore \, \frac{p_A}{p_B} = \sqrt{\frac{r_B}{r_A}} = \sqrt{\frac{ R+3R}{R+R}} = \sqrt{2}