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Question: Two identical rods with different thermal conductivities K<sub>1</sub> and K<sub>2</sub> and differe...

Two identical rods with different thermal conductivities K1 and K2 and different temperatures are first placed along length and then along area, then the ratio of rates of heat flow in both cases is –

A

4K1K2(K1+K2)2\frac{4K_{1}K_{2}}{(K_{1} + K_{2})^{2}}

B

K1K2\frac{K_{1}}{K_{2}}

C

K1+K2K1K2\frac{K_{1} + K_{2}}{K_{1}–K_{2}}

D

None of these

Answer

4K1K2(K1+K2)2\frac{4K_{1}K_{2}}{(K_{1} + K_{2})^{2}}

Explanation

Solution

KS = 2K1K2K1+K2\frac{2K_{1}K_{2}}{K_{1} + K_{2}}, KP = K1+K22\frac{K_{1} + K_{2}}{2}

HSHP\frac{H_{S}}{H_{P}} = KSKP\frac{K_{S}}{K_{P}} = 4K1K2(K1+K2)2\frac{4K_{1}K_{2}}{(K_{1} + K_{2})^{2}}