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Question

Physics Question on Moment Of Inertia

Two identical rods of length L, mass M are riveted at right angles at their mid points Moment of inertia of the system about the perpendicular axis passing through the centre is

A

ML2ML^2

B

ML212 \frac{ML^2}{12}

C

ML24 \frac{ML^2}{4}

D

ML26 \frac{ML^2}{6}

Answer

ML26 \frac{ML^2}{6}

Explanation

Solution

Inet=I1+I2I_{net} = I_1 + I_2
=2I= 2I
=2ML212= 2 \frac{ML^2}{12}
=ML26= \frac{ML^2}{6}