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Question: Two identical rods are made of different materials whose thermal conductivities are k<sub>1</sub> an...

Two identical rods are made of different materials whose thermal conductivities are k1 and k2. They are placed end to end between two heat reservoirs at temperature q1 and q2. The temperature of the junction of the rod is –

A

θ1+θ22\frac{\theta_{1} + \theta_{2}}{2}

B

k1θ1+k2θ22\frac{k_{1}\theta_{1} + k_{2}\theta_{2}}{2}

C

k1θ2+k2θ1k1+k2\frac{k_{1}\theta_{2} + k_{2}\theta_{1}}{k_{1} + k_{2}}

D

k1θ1+k2θ2k1+k2\frac{k_{1}\theta_{1} + k_{2}\theta_{2}}{k_{1} + k_{2}}

Answer

k1θ1+k2θ2k1+k2\frac{k_{1}\theta_{1} + k_{2}\theta_{2}}{k_{1} + k_{2}}

Explanation

Solution

In series the rate of heat flow is same

θ1θlk1A\frac{\theta_{1} - \theta}{\frac{\mathcal{l}}{k_{1}A}} = θθ2lk2A\frac{\theta - \theta_{2}}{\frac{\mathcal{l}}{k_{2}A}} Ž k1q1 – k1q = k2q – k2q2

q = k1θ1+k2θ2k1+k2\frac{k_{1}\theta_{1} + k_{2}\theta_{2}}{k_{1} + k_{2}}