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Question: Two identical prisms 1 and 2, each will angles of 30<sup>0</sup>, 60<sup>0</sup> and 90<sup>0</sup> ...

Two identical prisms 1 and 2, each will angles of 300, 600 and 900 are placed in contact as shown in figure. A ray of light passed through the combination in the position of minimum deviation and suffers a deviation of 300. If the prism 2 is removed, then the angle of deviation of the same ray is

A

Equal to 150

B

Smaller than 300

C

More than 150

D

Equal to 300

Answer

Equal to 150

Explanation

Solution

δ=(μ1)A\delta = ( \mu - 1 ) A as A is halved, so δ\deltais also halves