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Question

Physics Question on Oscillations

Two identical positive charges Q each are fixed at a distance of 2 a apart from each other. Another point charge q 0 with mass m is placed at midpoint between two fixed charges. For a small displacement along the line joining the fixed charges, the charge q 0 executes SHM. The time period of oscillation of charge q 0 will be

A

4π3ε0rna3q0Q\sqrt{\frac{4\pi^3ε0rna^3}{q0Q}}

B

qoQ4π3εrna3\sqrt{\frac{qoQ}{4\pi^3εrna^3}}

C

2π2ε0rna3q0Q\sqrt{\frac{2\pi^2ε_0rna^3}{q0Q}}

D

8π3ε0rna3q0Q\sqrt{\frac{8\pi^3ε_0rna^3}{q0Q}}

Answer

4π3ε0rna3q0Q\sqrt{\frac{4\pi^3ε0rna^3}{q0Q}}

Explanation

Solution

The correct option is(A): 4π3ε0rna3q0Q\sqrt{\frac{4\pi^3ε0rna^3}{q0Q}}

Two identical positive charges Q each are fixed at a distance of 2a apart from each other

(x << a) (α is acceleration)

Fnet=(kqoQ(ax)kQqo(a+x)2)F_{net}=-(\frac{kq_oQ}{(a-x)}-\frac{kQq_o}{(a+x)^2})

So, T=2π4π3ε0rna3q0QT=2\pi\sqrt{\frac{4\pi^3ε0rna^3}{q0Q}}