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Question: Two identical metallic spheres A and B carry charges +Q and –2Q respectively. The force between them...

Two identical metallic spheres A and B carry charges +Q and –2Q respectively. The force between them is F Newton, when they are separated by a distance d in air. The spheres are allowed to touch each other and are moved back to their initial positions. The force between them now is –

A

F/2

B

F/4

C

F/8

D

Zero

Answer

F/8

Explanation

Solution

F =

F ' = K(Q2)(Q2)r2\frac { \mathrm { K } \left( \frac { \mathrm { Q } } { 2 } \right) \left( \frac { \mathrm { Q } } { 2 } \right) } { \mathrm { r } ^ { 2 } }

F ' = F8\frac { F } { 8 }