Question
Question: Two identical metal spheres possess \(+60\;C\) and \(-20\;C\) of charges. They are bought in contact...
Two identical metal spheres possess +60C and −20C of charges. They are bought in contact and then separated by 10cm. The force between them is
& A.36\times {{10}^{13}}N \\\ & B.36\times {{10}^{14}}N \\\ & C.36\times {{10}^{12}}N \\\ & D.3.6\times {{10}^{12}}N \\\ \end{aligned}$$Solution
We know that the electric force is force experienced due to a pair charges being given by Coulomb's force. Clearly, the electric force depends on the charge q and inversely proportional to the square of the distance between them. Since the charges are brought to contact, there is some rearrangement of the charges. We can use the above to solve the given problem.
Formula used: E=4πϵ0r2q1q2
Complete step by step answer:
We know that electric force is the force between the given charges. This is given by Coulomb's law. From the coulomb's law, we know that, the electrical force F between two charges q1 and q2 which is separated at a distance r is given as
F∝q1q2 and F∝r21
Combining the two we have,⟹F∝r2q1q2
We can remove the proportionality, using a constant, then we have the coulomb's law of electric force is given as F=kr2q1q2,where k=4πϵ01 which is a constant with a value 9×109 .
Given that two charges q1=+60C and q2=−20 which is brought to contact, then the net charge is given as Q=60−20=40C. This net charge gets distributed equally.
This charge now gets separated at a distance r=10cm, then, we can say that Q1=20C and Q2=20C
Then the force between them is given as F=(10−1)29×109×20×20=36×1013N
So, the correct answer is “Option A”.
Note: We know that the electric force due to a pair of charges is given by Coulomb's law. This force can be attractive or repelling depending on the nature of the charges. An electric field can be produced by a time-varying electric field or an electrical charge. These can be either attracting or repelling in nature.