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Question

Physics Question on wave interference

Two identical light waves, propagating in the same direction, have a phase difference δ\delta. After they superpose the intensity of the resulting wave will be proportional to

A

cosδcos\, \delta

B

cos(δ/2)cos\, (\delta /2)

C

cos2(δ/2)cos^{2} (\delta/2)

D

cos2δcos^{2}\delta

Answer

cos2(δ/2)cos^{2} (\delta/2)

Explanation

Solution

The resulting intensity of two identical light waves, which have a phase difference of δ and propagate in the same direction, is
Ir=I+I+2Icosδ=4Icos2(δ2)I_r=I+I+2I\cosδ=4I\cos^2(\frac{δ}{2})
Therefore, the resulting intensity of the wave is directly proportional to cos2δ2\cos^2\frac{δ}{2}
So, the correct option is (C) : cos2(δ2)\cos^2(\frac{δ}{2})