Question

Two identical ideal springs of spring constant 1000 N/m are connected by a pulley as shown in figure and this arrangement is established in the vertical plane. The pulley is ideal and string passing over pulley is mass less. At equilibrium of pulley q is 60⁰ and the masses m₁ and m₂ are 2 kg and 3 kg respectively. Then the elongation in each spring when q is 60⁰ is –

• A. 1.6 $\sqrt { 3 }$ cm
• B. 1.6 cm
• C. 4.8 cm
• D. None

Answer 1

Answer: (A)

1.6 $\sqrt { 3 }$ cm

Answer 2

2kx cos 30⁰ = $\left( \frac { 4 m _ { 1 } m _ { 2 } } { m _ { 1 } + m _ { 2 } } \right) g$