Question

Two identical current carrying coils with same centre are placed with their planes perpendicular to each other. If i = $\sqrt{2}A$ and radius of coil R = 1 m, then magnetic field at centre C is equal to:

• A. $\mu_{0}$
• B. $\frac{\mu_{0}}{2}$
• C. $2\mu_{0}$
• D. $\sqrt{2}\mu_{0}$

Answer 1

Answer: (A)

$\mu_{0}$

Answer 2

$B_{0}=\sqrt{B^{2}_{1}+B^{2}_{2}}$
$B_{0}=\sqrt{2}B$
$B_{0}=\sqrt{2}\frac{\mu_{0}I}{2R}=\sqrt{2}\frac{\mu_{0}\times \sqrt{2}}{2\times 1}$ $=\mu_{0}$

So, the correct answer is (A): μ 0​