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Question: Two identical container contain equal amount of same ideal gas at temp T<sub>0</sub>, and pressure P...

Two identical container contain equal amount of same ideal gas at temp T0, and pressure P0. Now the two container is connected through a tube having negligible volume and one container is heated to 2T0 while other is kept at T0. The final common pressure is –

A

2P03\frac{2P_{0}}{3}

B

4P03\frac{4P_{0}}{3}

C

P03\frac{P_{0}}{3}

D

2 P0

Answer

4P03\frac{4P_{0}}{3}

Explanation

Solution

P0VRT0\frac{P_{0}V}{RT_{0}} + P0VRT0\frac{P_{0}V}{RT_{0}} = PVRT0\frac{PV}{RT_{0}} + PVR2T0\frac{PV}{R2T_{0}}

2 P0 = P + P2\frac{P}{2} or 2 P0 = 3P2\frac{3P}{2} or P = 4P03\frac{4P_{0}}{3}